Squonkapalooza / Community Spotlight

<p>Welcome to our first community spotlight episode</p><p>In this episode I talk to Lisa Russell from Cryptid Comforts about the upcoming Squonkapalooza festival.</p><p>Resource:</p><p><a href="https://squonkapalooza.com/" rel="nofollow">https://squonkapalooza.com/</a></p><p>Do you have an upcoming community event or individual that you would like me to spotlight and talk about? Nominate one by emailing me at bigfootsociety@gmail.com</p><p>_______</p><p>Join the only Facebook group for Van Meter Visitor fans - “Van Meter Visitor Believers” - See you there!</p><p><a href="https://www.facebook.com/groups/vanmetervisitorbelievers/?ref=share" rel="nofollow">https://www.facebook.com/groups/vanmetervisitorbelievers/?ref=share</a></p><p><br></p><p>FOR MORE INFO ON THE VAN METER VISITOR FESTIVAL:</p><p><a href="https://www.facebook.com/vanmetervisitorfestival/" rel="nofollow">https://www.facebook.com/vanmetervisitorfestival/</a></p><p>_______</p><p>Join us over on Patreon! Get access to extra audio content, exclusive merch like a membership card and stickers, watch me interview guests weekly live on video, a Patron-only Discord and more.</p><p><a href="https://www.patreon.com/thebigfootsociety" rel="nofollow">https://www.patreon.com/thebigfootsociety</a></p><p><br></p><p>Pick up a Bigfoot Society shirt to rep the podcast!</p><p><a href="https://www.etsy.com/shop/BigfootSociety" rel="nofollow">https://www.etsy.com/shop/BigfootSociety</a></p><p><br></p><p>Tune in for new episodes of Bigfoot Society!</p><p><a href="https://www.youtube.com/channel/UC8Qq45W6iaTU8FE9kelxT7Q" rel="nofollow">https://www.youtube.com/channel/UC8Qq45W6iaTU8FE9kelxT7Q</a></p><p><br></p><p>For full links go to:</p><p><a href="http://www.bigfootsocietypodcast.com/" rel="nofollow">www.bigfootsocietypodcast.com</a></p><br/><br/>Advertising Inquiries: <a href='https://redcircle.com/brands'>https://redcircle.com/brands</a><br/><br/>Privacy & Opt-Out: <a href='https://redcircle.com/privacy'>https://redcircle.com/privacy</a>